Russia's Sharapova beats World No. 1 Henin at Australian Open

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The former World No. 1, Russia's Maria Sharapova, reached the semifinals of the 2008 Australian Open on Tuesday after beating top-seed and current World No. 1, Justine Henin of Belgium.
MOSCOW, January 22 (RIA Novosti) - The former World No. 1, Russia's Maria Sharapova, reached the semifinals of the 2008 Australian Open on Tuesday after beating top-seed and current World No. 1, Justine Henin of Belgium.

The Russian, seeded 5, enjoyed a surprisingly easy straight sets victory, 6-4, 6-0 and will now face Jelena Jankovic (3) of Serbia in the semifinals. The Serb overcame the winner of the 2007 Australian Open, U.S. star Serena Williams (7), 6-3, 6-4, in her quarterfinal match on Tuesday.

Sharapova's victory in a match, which lasted almost an hour and 40 minutes, broke Henin's 33 match unbeaten streak.

The latest victory is the third time Sharapova has beaten Henin. She has lost to the Belgian six times. The first time Sharapova beat Henin was in 2005 at a tennis tournament in Miami, the United States, and the second time in the final of the 2006 U.S. Open tennis tournament.

Last year Sharapova reached the final of the 2007 Australian Open, where she lost to Serena Williams.

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